Name Of The Post: |
JKCE 2026 Jail Constable Recruitment |
Short Information of Post: |
JSSC Assistant Jailor Online Form 2026 notification has been officially released by the Jharkhand Staff Selection Commission (JSSC) under the 2025 recruitment campaign. This recruitment drive is a golden opportunity for candidates who want to build a career in government service in Jharkhand’s prison department. As per the official notice, the online application process will start from 09 January 2026 and will remain open till 08 February 2026. Interested and eligible candidates are advised to carefully read the complete notification related to eligibility, age limit, selection process, and other important instructions before applying online through the official JSSC website. |
Jharkhand Staff Selection Commission (JSSC): Short DetailsImportant Dates & Exam Fee For JSSC Assistant Jailor (Kakshpal) Online Form 2026. |
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Important Dates |
Exam Fee |
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GOVJOBTRACKER.COMAge Limit As Per 01.08.2025
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Total Posts |
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1733 |
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Education QualificationShould have passed at least Matriculation / 10th Class from an educational institution recognised by the Central or State Government. |
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Mode Of Selection
Level-2 (19,900–63,200) |
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How to Fill the JSSC Assistant Jailor (Kakshpal) Online Form 2025. |
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i) To fill out the application form, first visit the Commission’s official website www.jssc.jharkhand.gov.in and click on Online Application for JKCE-2025, then complete your registration process. ii) After the registration process is completed, your registration number and password will be sent to your mobile phone and email ID. iii) Once you receive the registration number and password, log in again and fill in all the required details about yourself. iv) After payment of the examination fee, upload your scanned photo and full signature. |
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IMPORTANT LINKS |
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Apply Online |
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Download Official Notification In PDF |
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Download Date Extend Notice |
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Download New Advertisement |
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Official Website |
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Join Our WhatsApp Channel |
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Join Our Telegram Channel |
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Category Wise Vacancy Details |
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| Candidates | General | EBC-1 | BC-2 | EWS | SC | ST | TOTAL |
| Male | 654 | 130 | 98 | 163 | 164 | 425 | 1634 |
| Female | 28 | 06 | 03 | 04 | 07 | 16 | 64 |
| Backlog Vacancy | |||||||
| Male | 00 | 03 | 03 | 00 | 02 | 11 | 19 |
| Female | 00 | 01 | 02 | 00 | 03 | 10 | 16 |
Physical Eligibility |
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| Candidates | Height | Chest | Running | ||||
| Male(General, EBC-1, BC-2, EWS) Candidates | 160 CM | 81 CM | 1600 Meter (In 06 Minutes) | ||||
| Male( SC/ST) Candidates | 155 CM | 79 CM | |||||
| Female All Category | 148 CM | NA | 1600 Meter (IN 10 Minutes) | ||||
Exam Pattern Syllabus |
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Exam Pattern
Main ExaminationThere will be three papers for the main examination. Paper – 1 (Language Knowledge)Total Questions: 120 (a) Hindi Language Knowledge – 80 questions Note: For Paper-I Qualifying Marks is at least 30% Paper – 2 (Tribal and Regional Language Knowledge)Objective Type Questions Total Questions: 100 Candidates can choose one language from the following options for this paper: Note: For Paper-II Qualifying Marks is at least 30%Paper – 3 (General Knowledge)General Knowledge (a) General Studies – 40 questions Note: For Paper-III Qualifying Marks is at least 30%Note:
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Frequently Asked Questions FAQs
07 नवंबर 2025 से।
08 दिसंबर 2025 लास्ट डेट है।
JSSC कक्षपाल 2025 की फीस कितनी है?
Minimum Age:- 18 Years
Maximum Age:- 28 Years
कक्षा 10 उत्तीर्ण।
www.jssc.jharkhand.gov.in
From November 7, 2025.
December 8, 2025 is the last date.
For General/OBC/EWS: Rs. 100/-
For SC/ST Candidates of Jharkhand: Rs. 50/-
Minimum Age:- 18 Years
Maximum Age:- 28 Years
Class 10 Passed.